求满足条件的abcd,e四位数

假设某个四位数满足abcd*e=dcba,a不等于0，e非0非1，找出满足条件的abcd和e

number is 2178 e is 4

/**
* @param args
* 假设某个四位数满足abcd*e=dcba,a不等于0，e非0非1，找出满足条件的abcd和e
*/
public static void main(String[] args) {

    //e>1,所以 abcd一定是在4999以内

    for(int e=2;e<9;e++)
    {
        for (int i = 1001; i < 4999; i++) {
            int resultNumb=i*e;
            if(resultNumb>9999)
            {
                break;
            }
            if(resultNumb==getReNumber(i))
            {
                System.out.println("number is "+i+" e is " +e);
            }
        }

    }



}
//假设某个四位数满足abcd*e=dcba,a不等于0，e非0非1，找出满足条件的abcd和e
private static int getReNumber(int num)
{
    //由于num一定是四位数，所以转换后
    int d=num%10;
    int c=num/10%10;
    int b=num/100%10;
    int a=num/1000;
    int result= d*1000+c*100+b*10+a;
    return result;

}

1089 9
2178 4