实现的是小写金额转换成大写金额，求求大神啦，在线等

我想要实现的是小写金额转换成大写金额，下边是我在网上找到的JS代码，我想问的是，我是不是只要将“numberValue”我想转变的小写金额就可以啦，求大神指导，我的需求就是把表格中一项“大写金额”变成大写。其实大写金额就是JSP页面上ruKu.shiJiJinE的值，请问各位大神怎么写

  <TR>
           <TD align="left" class="tdp">规格：</TD>
         <TD align="left" class="tdp" width="15%"><s:property value="ruKu.guiGe"/></TD>
           <TD align="left" class="tdp" >实际重量：</TD>
         <TD align="left" class="tdp" width="15%"><s:property value="ruKu.shiJiZongLiang"/></TD>
           <TD align="left" class="tdp">大写金额：</TD>
         <TD align="left" class="tdp" width="15%"><s:property value="  "/></TD>
        </TR>

function atoc(numberValue){  
var numberValue=new String(Math.round(numberValue*100)); // 数字金额  
var chineseValue=""; // 转换后的汉字金额  
var String1 = "零壹贰叁肆伍陆柒捌玖"; // 汉字数字  
var String2 = "万仟佰拾亿仟佰拾万仟佰拾元角分"; // 对应单位  
var len=numberValue.length; // numberValue 的字符串长度  
var Ch1; // 数字的汉语读法  
var Ch2; // 数字位的汉字读法  
var nZero=0; // 用来计算连续的零值的个数  
var String3; // 指定位置的数值  
if(len>15){  
alert("超出计算范围");  
return "";  
}  
if (numberValue==0){  
chineseValue = "零元整";  
return chineseValue;  
}  
String2 = String2.substr(String2.length-len, len); // 取出对应位数的STRING2的值  
for(var i=0; i<len; i++){  
String3 = parseInt(numberValue.substr(i, 1),10); // 取出需转换的某一位的值  
if ( i != (len - 3) && i != (len - 7) && i != (len - 11) && i !=(len - 15) ){  
if ( String3 == 0 ){  
Ch1 = "";  
Ch2 = "";  
nZero = nZero + 1;  
}  
else if ( String3 != 0 && nZero != 0 ){  
Ch1 = "零" + String1.substr(String3, 1);  
Ch2 = String2.substr(i, 1);  
nZero = 0;  
}  
else{  
Ch1 = String1.substr(String3, 1);  
Ch2 = String2.substr(i, 1);  
nZero = 0;  
}  
}  
else{ // 该位是万亿，亿，万，元位等关键位  
if( String3 != 0 && nZero != 0 ){  
Ch1 = "零" + String1.substr(String3, 1);  
Ch2 = String2.substr(i, 1);  
nZero = 0;  
}  
else if ( String3 != 0 && nZero == 0 ){  
Ch1 = String1.substr(String3, 1);  
Ch2 = String2.substr(i, 1);  
nZero = 0;  
}  
else if( String3 == 0 && nZero >= 3 ){  
Ch1 = "";  
Ch2 = "";  
nZero = nZero + 1;  
}  
else{  
Ch1 = "";  
Ch2 = String2.substr(i, 1);  
nZero = nZero + 1;  
}  
if( i == (len - 11) || i == (len - 3)){ // 如果该位是亿位或元位，则必须写上  
Ch2 = String2.substr(i, 1);  
}  
}  
chineseValue = chineseValue + Ch1 + Ch2;  
}  
if ( String3 == 0 ){ // 最后一位（分）为0时，加上“整”  
chineseValue = chineseValue + "整";  
}  
return chineseValue;  
}  

string changNum = "";
double moneyNum=132457689.129;
char[] strMoney = moneyNum.ToString().ToCharArray();
for (int i = 0; i < strMoney.Length; i++)
{
switch (strMoney[i].ToString())
{
case"0":
changNum += "零";
break;
case "1":
changNum += "壹";
break;
case "2":
changNum += "贰";
break;
......
}
}