jquery的slideToggle方法的实现问题,求改错没法显示

<div class="serlist_box serlist_box_even" id="<?php echo $value["id"]; ?>">
            <ul class="serlist_box_inner clearfix">
                            <li class="serlist_bd_station serlist_bd_station_tow">
                            <a class="stopdetail<?php echo $value["id"]; ?> 
                            first_last_station" href="javascript:;">
                     <p class="icon_depart clearfix" style="color:#06c;font-size:13px;"><i ></i><span><?php echo $value["detail"]; ?></span></p>
                     <b class="icon_hide"></b>
                   </a> </li>
  <li class="serlist_bd_station_jingting_li serlist_bd_station_jingting<?php echo $value["id"]; ?> jingting_xianlu" style="display:none" id="<?php echo $value["id"]; ?>">
                    <b>经停站：</b><span style="color:#000;font-size:13px;"><?php echo $value["station"]; ?></span>
              </li></ul>

                  <script>
         $(document).ready(function(){  
         $(".stopdetail<?php echo $value["id"]; ?>").click(
         function(){
                   $(".serlist_bd_station_jingting<?php echo $value["id"]; ?>")).slideToggle(300);
                   $(".serlist_bd_station_jingting<?php echo $value["id"]; ?>")).closest("div").siblings().find("li").slideUp();
                   return false
          });
        });
        </script> 

多了一个反括号了

                   $(".serlist_bd_station_jingting<?php echo $value["id"]; ?>").slideToggle(300);
                   $(".serlist_bd_station_jingting<?php echo $value["id"]; ?>").closest("div").siblings().find("li").slideUp();

多了一个反括号了
$(".serlist_bd_station_jingting<?php echo $value["id"]; ?>").slideToggle(300);
$(".serlist_bd_station_jingting<?php echo $value["id"]; ?>").closest("div").siblings().find("li").slideUp();