在action中如何获取ServletConfig

HttpServletRequest request=ServletActionContext.getRequest();
HttpServletResponse response=ServletActionContext.getResponse();
SmartUpload smartUpload=new SmartUpload();

    try {
    //当执行到下面这句时程序就跳异常
    smartUpload.initialize(ServletActionContext.getPageContext().getServletConfig(), request, response);
    smartUpload.upload();
    int size = Integer.parseInt(smartUpload.getRequest().getParameter(
            "fileNumber"));
    for (int i = 0; i < size; i++) {
        com.jspsmart.upload.
        ....

试试这个：

 ServletConfig sconfig = (ServletConfig)request.getSession().getServletContext().getAttribute("servletConfig");

sconfig为null