select name,course as mincourse,score as minscore from userscore ore in(select min(score) from userscore group by name) group by name;
select name,course as mincourse,score as minscore from userscore ore in(select min(score) from userscore group by name) group by name;
怎么用一条语句写啊?
光分数相当还是不够的,如果甲分数99,90,80,乙分数90,80,70,你的结果就是错的。应该同时分数相等,人一致才行
select name,course as mincourse,minscore from userscore u,
(select name,min(score) minscore from userscore group by name) mu
where u.name = mu.name and u.score=mu.score
那你最好在设计表的时候设计成
学号 课程id 分数
这样比较好统计
select * from table where g=max(g) or g=min(g);
你可以用上面的语句试试看
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