import java.util.*;
public class NewHashTest
{
public static void main(String[] args)
{
HashMap hash = new HashMap();
Emp emp1 = new Emp("laoda","111",123f);
Emp emp2 = new Emp("laoer","222",234f);
Emp emp3 = new Emp("laosan","333",5466f);
hash.put(111,emp1);
hash.put(222,emp2);
hash.put(333,emp3);
if(hash.containsKey(111))
{
Emp em = (Emp)hash.get(111);
em.info();//可以正常显示
}
Iterator iter = hash.keySet().iterator();
while(iter.hasNext())
{
String key = iter.next().toString();
Emp ems = (Emp)hash.get(key);
ems.info();//这里会报错
}
}
}
class Emp
{
String name;
String number;
float slary;
public void info()
{
System.out.println("名字叫:"+name);
System.out.println("编号为:"+number);
System.out.println("薪水是:"+slary);
}
public Emp(String name,String number,float slary)
{
this.name = name;
this.number = number;
this.slary = slary;
}
}
会在ems.info();一行报一个Exception in thread "main" java.lang.NullPointerException的错误,是不是传入的KEY类型有问题,还是什么别的问题,求指点。
map设置的键值对的时候键 hash.put(111,emp1) 111为int类型,而遍历的时候确
String key = iter.next().toString();
使用String类型作为查找的key,当然就会是null了。
可将111 222 改成字符