2.输入一段连续的英文字符串，统计所有英文字母出现的次数并输出。（map容器）。已解决只是还有漏洞

#include
#include
#include
#include
#include

using namespace std;

void main(){
mapcount;
map::iterator it;
printf("please enter a paragraph of English character:\n");

string str;
cin>>str;
for(int i=0;i<str.length();i++)
{
    if(count.find(str[i])!=count.end ())
        count[str[i]]++;
    else
        count[str[i]]=1;
}
for(it=count.begin();it!=count.end();it++)
{   
    printf("字母%c出现的次数为：%d",it->first,it->second);
    printf("\n");
}

}

https://blog.csdn.net/cmm0401/article/details/80411595