from s in ssfrom e in ee.Where(e => s.x == e.y)如题,如何将where中的lambda以Expression类型作为参数传递?类似
Expression<Func<T, bool>> Lambda = a => a==1; var aa = _DbContext._T.Where(Lambda.Compile());
var aa = _DbContext._T.Where(Lambda);这样就可以,不要compile