要求使用C语言，将一个字符串逆序，以下是我的代码，一直编译不出结果，哪位大佬帮个忙，谢谢啦

 #include <stdio.h>                                             
 #include <stdlib.h>
 #include <string.h>

 char * Reverse_Order(const char *str);
 int main(int argc,const char* argv[])
 {
     char *str = "hello";
     printf("逆序后为:%s\n", Reverse_Order(str));
     free(Reverse_Order(str));
     return 0;
 }   


 char * Reverse_Order(const char *str)
 {
     char *Reverse = NULL;
     Reverse = (char *)malloc(10);
     int num = 0;
     while(*str != '\0')
     {
         str += 1; 
         num++;
     }   

     while(*str != '\0')
     {
         int i=0;
         Reverse[i++] = str[num--];
     }   
     return Reverse;
 }   

问题解决的话，请点下采纳

#include <stdio.h>                                             
#include <stdlib.h>
#include <string.h>

char * Reverse_Order(const char *str);
int main(int argc,const char* argv[])
{
    char str[] = "hello";
    char *  p  = Reverse_Order(str);
    printf("逆序后为:%s\n", p);
    free(p);
    return 0;
}   


char * Reverse_Order(const char *str)
{
    char *Reverse = NULL;
    const char *str1 = str;
    Reverse = (char *)malloc(10);
    int num = 0;
    while((*str) != '\0')
    {
        str += 1; 
        num++;
    }   
    int i = 0;
    while(i < num)
    {
        Reverse[i++] = str1[num-i-1];
    } 
    Reverse[i] = '\0';
    return Reverse;
}   

1楼回复的代码有个bug,

Reverse[i++] = str1[num-i-1];
需要修改为
Reverse[i] = str1[num-i-1];
i++;