切片的（整数）索引作为结构数组

Is it possible in Go create array with where each element of array will be array of slices or structures.

Something like in PHP

    $a = [1=>"test", 2=>""]
    // in this example 2 is integer will be for GoLang?
    $a[2] = [ object, object, object ]

Can I do in Go something like ? I know about incorrect syntax.

   var a [int][]StructureName

   b := make([]StructureName, 0)
   b := append ( b, StructureName{a, b, c, d})
   b := append ( b, StructureName{e, f, g, h})

   a[0] = append (a[0][0], b)

`/*
[
1 => [
    ‘username1’, <-- string element
    ‘events’=>[ <-- array of structures
        object1, <-- structure
        object2, <-- structure
        object3 <-- structure
        ]
    ],
2 => [ <-- next record
    ‘username2’,
    ‘events’=>[
        object1,
        object2,
        object3
        ]
    ]
]
*/
`

You can use map and map it from int => interface{}.

package main

import (
    "fmt"
)

func main() {
    m := make(map[int]interface{})
    var x []interface{}
    x = append(x, "username")
    x = append(x, []int{3, 1, 3})
    m[1] = x
    fmt.Println(m)
}

https://play.golang.org/p/B_dsvARic8c

Hope this helps.

Declare types that match the structure of the data. This ensures type safety and avoids the need to type assert when accessing the data.

In this case, it looks like you need a slice of structs where on of the fields is also a slice of event structs.

type Event struct {
    // Even fields TBD
}

type User struct {
    Name string
    Events []*Event
}

var users []*User

users = append(users, &User{
    Name: "name1",
    Events: []*Event{ object1, object2, object3 },
})