Hi Golang newbie here,
How to pass a variable as pointer argument to the another function.
func B(temp *?, event *Event) {
temp["filla_a"] = event.Data["filla_a"]
return temp
}
func A(event *Event) {
temp := make(map[string]interface{})
temp["po_id"] = event.Data["id"]
temp = B(temp, event)
}
How to achive this in golang ?
This is how you can do it in go:
package main
import (
"fmt"
)
type Event struct {
Data map[string]string
}
func main() {
e := new(Event)
e.Data = make(map[string]string)
e.Data["id"] = "THE_ID"
e.Data["filla_a"] = "THE_FILLA_A"
A(e)
}
func A(event *Event) {
temp := make(map[string]interface{})
temp["po_id"] = event.Data["id"]
B(temp, event)
fmt.Println(temp)
}
func B(temp map[string]interface{}, event *Event) map[string]interface{}{
temp["filla_a"] = event.Data["filla_a"]
return temp
}
I have assumed/made event as struct and declared the same in the program.
The map in go is a reference type (or better say it has pointer reference to internal data structures), so you do not need to pass a pointer of map, just pass/return the variable itself.
On the other hand struct (the Type of e in the main() function) is value type and need to be passed as a pointer to persist updates from called function.
NOTE: the new keyword creates a pointer to the type. Thus the variable e in the main() function is actually a pointer to the Type Event.
Go Playground: https://play.golang.org/p/Jbkm6z5a2Az
Hope it helps.