My Form page :
<body>
<head>
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script>
function val()
{
var name=document.getElementById("name").value;
if(name == '')
{
alert(name+" is empty");
}
else
{
var dataString = "name = "+name;
$.ajax({
type:"POST",
url:"hi.php",
data:dataString,
cache:false,
success:function(html){
$('#msg').html(html);
}
});
}
return false;
}
</script>
</head>
<body>
<form>
<input type="text" id="name" >
<br/><br/>
<input type="submit" value ="submit" onclick="return val()">
</form>
<p id="msg"></p>
</body>
Here is my hi.php file
<?php
$name = $_POST["name"];
echo "Response : ".$name;
?>
When clicking on submit button it show an error Notice: Undefined index: name in C:\wamp\www\SendEmailAjaxJquery\hi.php on line 2
I don't know where is the error plz help me to find out the error...
Thanks in advance
Use this in place of this
var dataString = "name = "+name;
change into this
var dataString = 'name='+ name;
i have the same case here you will be guided from it.
<html>
<head>
<script type="text/javascript" src="jquery-1.12.3.min.js"></script>
</head>
<body>
<div class="content">
<input type="text" class="search" id="searchid" placeholder="Search for people" />
<div id="result"></div>
</div>
</body>
</html>
<script type="text/javascript">
$(function(){
$(".search").keyup(function()
{
var searchid = $(this).val();
var dataString = 'search='+ searchid;
if(searchid!='')
{
$.ajax({
type: "POST",
url: "result.php",
data: dataString,
cache: false,
success: function(html)
{
$("#result").html(html).show();
}
});
}return false;
});
in your ajax data change to
data:{ 'name' : name }
Change to:
$.ajax({
type:"POST",
url:"hi.php",
data: {name: name},
cache:false,
success:function(html){
$('#msg').html(html);
}
});
jQuery ajax data setting accept Object to customize the key. For example:
data: {anything: "123"}
In PHP:
echo $_POST["anything"]; //123