如何在Javascript上将PHP串起来

My code:

var page = 1;
        $(window).scroll(function () {
            $('#more').hide();
            $('#no-more').hide();
            if($(window).scrollTop() + $(window).height() > $(document).height() - 200) {
                $('#more').css("top","400");
                $('#more').show();
            }
            if($(window).scrollTop() + $(window).height() == $(document).height()) {
                $('#more').hide();
                $('#no-more').hide();
                page++;
                var data = {
                    page_num: page
                };
                var actual_count = "<?php echo $actual_row_count; ?>";
                if((page-1)* 2 > actual_count){
                    $('#no-more').css("top","400");
                    $('#no-more').show();
                }else{
                    $.ajax({
                        type: "POST",
                        url: "search-data.php/?search=<?php echo $search ?>", // <---- Here Problem
                        data:data,
                        success: function(res) {
                            $("#result").append(res);
                            console.log(res);
                        }
                    });
                }
            }
        });

on the file search-data.php:

$search = $_GET['search']; // no string 

Change your ajax request to GET

$.ajax({
    type: "GET",
    url: "search-data.php/?search=<?php echo $search ?>",
    data:data,
    success: function(res) {
        $("#result").append(res);
        console.log(res);
    }
});

Thanks for your answer "Morteza"

 $.ajax({
       type: "GET",
       url: "search-data.php/?search=<?php echo $_GET['search'] ?>&page=+data.page_num",
       data:data,
       success: function(res) {
       $("#result").append(res);
       console.log(res);
                        }
                    });

Thankyou very much :D

Regard's

Grenz

its post request change to

$search = $_POST['search'];

or change in your script

$.ajax({
                        type: "GET",
                        url: "search-data.php/?search=<?php echo $search ?>", // <---- Here Problem
                        data:data,
                        success: function(res) {
                            $("#result").append(res);
                            console.log(res);
                        }
                    });

Either during your ajax call, use type : 'get' or in search-data.php use $_POST Superglobal to fetch the data.