When I submit a variable into a form and submit it to a PHP file which is in turn connected to MySQL server, this happens:
Notice: Use of undefined constant project - assumed 'project' in C:\xampp\htdocs\projectsday\project-phpfile.php on line 3
Notice: Use of undefined constant databse - assumed 'databse' in C:\xampp\htdocs\projectsday\project-phpfile.php on line 3
Why is this so? Last time I tried, it was fine, but it doesn't work only today.
Line 3:
$db=mysql_select_db(project-databse,$con) or die("Failed to connect to MySQL: " . mysql_error());
The 'databse' is not misspelled. Thank you for your help.
The function mysql_select_db expects parameter 1 to be a string (http://php.net/manual/en/function.mysql-select-db.php).
If you haven't defined a string constant named project-databse (it's not possible with -, because the server will try to substract both constants) you should try to put in the name as a string, using ''.
db=mysql_select_db('project-databse',$con) or die("Failed to connect to MySQL: " . mysql_error());
Try to use underscore in your constant name: project_databse, instead of project-databse Constants cannot contain '-' character. Your server recognized your costant as two different constants, that's why you have two different notices
It's not possible it was working.
At the moment if you use:
project-databse
PHP assumes you have 2 constants: project and databse and you do substraction for them.
So probably earlier it was: 'project-databse' with quotes.