php可以使用下拉菜单在XML调用中提取变量集

Hi I am new to this forum and hoping someone could help I have set a dropdown menu with option value dynamically pulling in from a mysql database. these values when selected use xml to return the ids and content according to whats been selected. In the url there is a variable which im having trouble getting PHP to create a session variable from it. Can this be done? Thanks

Thanks, this is the code where the url is set

function showUser(str) { var xmlhttp; if (str.length==0) { document.getElementById("state").innerHTML=""; return; } if (window.XMLHttpRequest) { xmlhttp=new XMLHttpRequest(); } else{ xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("state").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","getuser.php?q="+str,true); xmlhttp.send(null); }

The php call '$id = $_GET['q']; $_SESSION['q'] = $id;'

Do you mean this?

http://www.domain.com/?action=delete

$action = $_GET['action'];
$_SESSION['action'] = $action;