从HTML表单获取值并将其传递到同一页面

I don't often work with forms, so something as trivial as passing a form selection into the same page seems quite challenging. I've checked a bunch of stackoverflow's questions on this, but they never say where to place the _POST code or they post the code to another page. I know I'm doing something the wrong way, that's probably pretty simple. Can anybody help me out?

numbersPage.php

<?php 
session_start();
$_POST['here'];
$hello = $_GET['here'];

echo $hello;
?>

<!DOCTYPE html>
<html>
<head>
    <meta charset="utf-8">

</head>

<form name="input" action="numbersPage.php" method="get">
Fav Number: 
<select id="">
  <optgroup label="Numbers">
    <option value="1" name="thing">1</option>
    <option value="2" name="thing">2</option>
    <option value="3" name="thing">3</option>
    <option value="4" name="thing">4</option>
    <option value="5" name="thing">5</option>


  </optgroup>
</select>
<input type="submit" value="Submit">

</form>


</body>
</html>

You missed to give the <select> a name. use this:

<select name="here">

The value of the name attribute of a form element will be the index in the $_GET array. Also note that this:

$_POST['here'];

is just pointless. I'm not sure what you are expecting from that. Remove that line.

If the code is simple as you showed you also remove this line:

session_start();

Further note that you should in any case check if a value has been properly submitted before using it:

if(!isset($_GET['here'])) {
    die('GET:here is missing');
} else {
    $here = $_GET['here'];
    // the value has been submitted. Now validate it!
    if(!is_valid($here)) {
        die('Bad input');
    }
}

// further processing.

you are doing right but you have to do more like

if(isset($_REQUEST['submit1'])){

$_POST['here'];
$hello = $_GET['here'];

echo $hello;

}

remember one more thing, give a name to button

<input type="submit" value="Submit" name="submit1">