减少3个多个路由到一个功能？

I've been looking all over online and can't find anything that tells you how to assign multiple routes to one callback. For example I want to move:

$app->get('/sign-in', function($request, $response) {
    return $this->view->render($response, 'home.twig');
});

$app->get('/login', function($request, $response) {
    return $this->view->render($response, 'home.twig');
});

into something like:

$app->get(['/sign-in', '/login'], function($request, $response) {
    return $this->view->render($response, 'home.twig');
});

Is there a way to do this with Slim 3? I found online that in Slim 2 you could use the conditions([]); function on the end to chain multiple routes to one callback.

It seems that you can simply define an array and loop through it to create multiple routes on one funciton.

$routes = [
    '/',
    '/home', 
    '/sign-in',
    '/login',
    '/register',
    '/sign-up',
    '/contact'
];

foreach ($routes as $route) {
    $app->get($route, function($request, $response) {
        return $this->view->render($response, 'home.twig');
    });
}

Just create the function as a closure and pass it as a parameter:

$home = function($request, $response) {
    return $this->view->render($response, 'home.twig');
};

$app->get('/sign-in', $home);

$app->get('/login',   $home);

Or use a named function:

function home($request, $response) {
    return $this->view->render($response, 'home.twig');
};
$app->get('/sign-in', 'home');

$app->get('/login',   'home');

FastRoute doesn't do what you want, however, you can use a parameter that is limited via regex to the list of urls that you want to use:

$app->get("/{_:sign-in|login}", function ($request, $response) {
    $response->write("Hello!");
    return $response;
});

Note that you have to have an argument name, so I've use _ as it's inoffensive.

I am using regex to do this trick:

$app->get('/{router:login|sign-in}', function ($request, $response, $args) {
  echo "Hello, " . $args['router'];
});