I have this code
<html>
<body>
<table cellpadding="5" cellspacing="1" >
<tbody class="ui-widget"><form method="post" action="xx.php">
<tr>
<td><strong>Name</strong><br />
<input name="name">
</td>
</tr>
<button name='button'>Success Button</button>
</form></div>
<?php
if(isset($_POST['button']))
{ echo "BYE BYE";}
?>
Now the question is: if a click on button I'll obtain the form and after the word "BYE BYE"
How can I do if I want have only "BYE BYE" but in the same page?
There's a way for don't show another time the HTML code?
You need to place your PHP before your HTML and make a if/else :
<?php
if(isset($_POST['button'])) {echo "BYE BYE";}
else {
?>
<html>
<body>
<table cellpadding="5" cellspacing="1" >
<tbody class="ui-widget">
<form method="post" action="xx.php">
<tr>
<td><strong>Name</strong><br />
<input name="name">
</td>
</tr>
<button name='button'>Success Button</button>
</form>
</div>
<?php } ?>
You are outputting HTML before the PHP code is executed. It is not affected by the if-statement at the moment. To fix your specific issue, move the if-statement to the top and put the HTML-code in the else statement. Something like this should work:
<?php
if (isset($_POST['button'])) {
echo 'BYE BYE';
} else {
?>
<html>
<body>
<table cellpadding="5" cellspacing="1" >
<tbody class="ui-widget"><form method="post" action="xx.php">
<tr>
<td><strong>Name</strong><br />
<input name="name">
</td>
</tr>
<button name='button'>Success Button</button>
</form></div>
<?php
}
Note that checking for a POST-request is more reliable by checking the $_SERVER its REQUEST_METHOD index.