Why is the output to this 20, and not 22? Seeing as you're adding 10 + 0xA(which is 10 in HEX) + 2.
$a = 010;
$b = 0xA;
$c = 2;
print $a + $b + $c;
Output: 20.
It's correct!
(Because the first number is octal so if you want it to be interpreted as a decimal you have to remove the first 0) Se:
$a = 010; //Octal -> 8
$b = 0xA; //Hex -> 10
$c = 2; //Dec -> 2
print $a + $b + $c; //20
Output:
20
To use octal notation, precede the number with a 0 (zero). To use hexadecimal notation precede the number with 0x. To use binary notation precede the number with 0b.
010 is an octal number (it starts with a 0 which isn't followed by a decimal point), which is 8 in decimal.
This will solve:
<?php
$a = 10;
$b = 0xA;
$c = 2;
print $a + $b + $c;
?>
The 0 leading for $a was putting is as an Octal value, not decimal one.