如何在不编写长查询的情况下查询所有GraphQL类型字段？

Assume you have a GraphQL type and it includes many fields. How to query all the fields without writing down a long query that includes the names of all the fields?

For example, If I have these fields :

 public function fields()
    {
        return [
            'id' => [
                'type' => Type::nonNull(Type::string()),
                'description' => 'The id of the user'
            ],
            'username' => [
                'type' => Type::string(),
                'description' => 'The email of user'
            ], 
             'count' => [
                'type' => Type::int(),
                'description' => 'login count for the user'
            ]

        ];
    }

To query all the fields usually the query is something like this:

FetchUsers{users(id:"2"){id,username,count}}

But I want a way to have the same results without writing all the fields, something like this:

FetchUsers{users(id:"2"){*}}
//or
FetchUsers{users(id:"2")}

Is there a way to do this in GraphQL ??

I'm using Folkloreatelier/laravel-graphql library.

Unfortunately what you'd like to do is not possible. GraphQL requires you to be explicit about specifying which fields you would like returned from your query.

I guess the only way to do this is by utilizing reusable fragments:

fragment UserFragment on Users {
    id
    username
    count
} 

FetchUsers {
    users(id: "2") {
        ...UserFragment
    }
}

I faced this same issue when I needed to load location data that I had serialized into the database from the google places API. Generally I would want the whole thing so it works with maps but I didn't want to have to specify all of the fields every time.

I was working in Ruby so I can't give you the PHP implementation but the principle should be the same.

I defined a custom scalar type called JSON which just returns a literal JSON object.

The ruby implementation was like so (using graphql-ruby)

module Graph
  module Types
    JsonType = GraphQL::ScalarType.define do
      name "JSON"
      coerce_input -> (x) { x }
      coerce_result -> (x) { x }
    end
  end
end

Then I used it for our objects like so

field :location, Types::JsonType

I would use this very sparingly though, using it only where you know you always need the whole JSON object (as I did in my case). Otherwise it is defeating the object of GraphQL more generally speaking.

Yes, you can do this using introspection. Make a GraphQL query like (for type UserType)

{
   __type(name:"UserType") {
      fields {
         name
         description
      }  
   }
}

and you'll get a response like (actual field names will depend on your actual schema/type definition)

{
  "data": {
    "__type": {
      "fields": [
        {
          "name": "id",
          "description": ""
        },
        {
          "name": "username",
          "description": "Required. 150 characters or fewer. Letters, digits and @/./+/-/_ only."
        },
        {
          "name": "firstName",
          "description": ""
        },
        {
          "name": "lastName",
          "description": ""
        },
        {
         "name": "email",
          "description": ""
        },
        ( etc. etc. ...)
      ]
    }
  }
}

You can then read this list of fields in your client and dynamically build a second GraphQL query to get all of these fields.

This relies on you knowing the name of the type that you want to get the fields for -- if you don't know the type, you could get all the types and fields together using introspection like

{
  __schema {
    types {
      name
      fields {
        name
        description
      }
    }
  }
}

NOTE: this is the over-the-wire GraphQL data -- you're on your own to figure out how to read and write with your actual client. Your graphQL javascript library may already employ introspection in some capacity, for example the apollo codegen command uses introspection to generate types.