在PHP中显示字符串中的第一个和最后五个字符[关闭]

I want to display first and last 5 character from following string.

APA91bGjUqf8O8yoajdN9BNf2Hs1iVm3VL37X7rn1_XiU1bcKOWVyaIYYusL8f5BCgzSw1HhaPbgntuYHFCR0VWrqGb59nDHMVfgJ-zK0SA0SWw0dvdMEB8AwI-Ltn56aBb0L-0tP_pkqZIbPltb71-u6inawaPfQw

I want following output:

APA91...aPfQw

How to solve?

Use use this code. But you can do with preg_match too

$input  = 'your_string';
$output = substr($input, 0, 5) . substr($input, -5);

echo substr('APA91bGjUqf8O8yoajdN9BNf2Hs1iVm3VL37X7rn1_XiU1bcKOWVyaIYYusL8f5BCgzSw1HhaPbgntuYHFCR0VWrqGb59nDHMVfgJ-zK0SA0SWw0dvdMEB8AwI-Ltn56aBb0L-0tP_pkqZIbPltb71-u6inawaPfQw', 0, 5) . '...' .substr('APA91bGjUqf8O8yoajdN9BNf2Hs1iVm3VL37X7rn1_XiU1bcKOWVyaIYYusL8f5BCgzSw1HhaPbgntuYHFCR0VWrqGb59nDHMVfgJ-zK0SA0SWw0dvdMEB8AwI-Ltn56aBb0L-0tP_pkqZIbPltb71-u6inawaPfQw', -5, 5);

echo substr($str,0,5).'...'.substr($str,-5)

You can use the following:

if(strlen($input) > 10) {
  echo substr($input, 0, 5) . '...' . substr($input, -5);
} else {
  echo $input;
}

This will check the length of the $input first. In case less than 10 characters, that is meaningless to add ... in the string.

$input  = 'APA91bGjUqf8O8yoajdN9BNf2Hs1iVm3VL37X7rn1_XiU1bcKOWVyaIYYusL8f5BCgzSw1HhaPbgntuYHFCR0VWrqGb59nDHMVfgJ-zK0SA0SWw0dvdMEB8AwI-Ltn56aBb0L-0tP_pkqZIbPltb71-u6inawaPfQw';
$output = substr($input, 0, 5) ."...". substr($input, -5);

This is what you need :)

Wayne