将全局范围var传递给包含的文件

I'm trying to get a global var to show up in an included file. I'll replicate the path here:

$var = array();

funcA 
{
    global $var;
    $var = array('some'=>'values');

    funcB
    {
        global $var;

        //$var prints('some'=>'values')
        include_once('myfile.php');
    }
}

OR

funcA 
{
    $var = array('some'=>'values');

    funcB($var)
    {
        //$var prints('some'=>'values')
        include_once('myfile.php');
    }
}
myfile.php:
//prints own content (is included)
//$var is empty, whether declared global or not.

Am I missing a step?

EDIT: Before the upvote train of 'not using global variables' leaves me without an actual answer, the above still does not work even when $var is passed as a parameter from funcA to funcB. I have edited the code to demonstrate.

The file is included via file path, not url, but does reside in another directory - is that relevant?

EDIT: Even when initialising a variable just before including the file, the value is not passed to that file. The issue seems to be in the include method itself. I'm using include_once() and providing the full absolute path to the file.

Why not pass as a parameter and/or use return values? Your application shouldn't need to reply on globals, and is usually a sign of a design flaw.

function getVar() {
    return array('some'=>'values');
}

function printVar($var) {
    include_once('myfile.php');
    // print_r($var);
}

$var = getVar();
printVar($var);

If your problem is larger than the example shows, you should take a look at PHP's OOP and start using classes/objects. Check out some frameworks to help you dive right in too.