Based on information here MySQL query String contains trying to create pdo query with ?
Experimented with following
SELECT * FROM Table WHERE Column LIKE %?%
SELECT * FROM Table WHERE Column LIKE ?%
SELECT * FROM Table WHERE Column LIKE %?
Nothing works. Get error
Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '%...
Tried with SELECT * FROM Table WHERE Column LIKE ? but this is not for contains
Aim is to get query SELECT * FROM Table WHERE Column contains ?
What is is correct pdo contains statement for positional placeholders (?)?
try this by concatenating the value in the string via PHP,
$value = "valueHere";
$passThis = "%" . $value . "%";
// other pdo codes...
$stmt = $dbh->prepare("SELECT * FROM Table WHERE Column LIKE ?");
$stmt->bindParam(1, $passThis);
// other pdo codes...
after like add quotes. eg:- like '%?%'
i.e:
SELECT * FROM table_name WHERE column_name like '%field_name%';
If you would like to use prepared statements then take a look at http://php.net/manual/de/pdo.prepared-statements.php.
SELECT * FROM REGISTRY where name LIKE '%?%'
I think wildcard stament should be within single quotes, like;
SELECT * FROM Table WHERE Column LIKE '%?%';
This returns any record which contains the string given anywhere within the particular column field
Column data which starts with 'ber', example
SELECT * FROM Table WHERE Column LIKE 'ber%';
Hope this helps
Either put the % characters before and after your parameter before you pass it into the query or
SELECT * FROM Table WHERE Column LIKE '%' + ? + '%'
SELECT * FROM Table WHERE Column LIKE ? + '%'
SELECT * FROM Table WHERE Column LIKE '%' + ?
Although this will fail if ? is null because the concatenate will yield null. you could use coalesce
SELECT * FROM Table WHERE Column LIKE '%' + Coalesce(?,'') + '%'
SELECT * FROM Table WHERE Column LIKE Coalesce(?,'') + '%'
SELECT * FROM Table WHERE Column LIKE '%' + Coalesce(?,'')