阅读上传的所有文件行

I know this subject already exist but in my case is a little more difficult.

I'm reading .EDI files (current succeed) on PHP, the process:

1.- I upload a .edi file from a html form. 2.- I send those attributes from the form to read on my php code.

I got the code like this:

if(isset($_FILES['ufile']['name'])){
   $tmpName = $_FILES['ufile']['tmp_name'];
   $newName = "" . $_FILES['ufile']['name'];   
   if(!is_uploaded_file($tmpName) ||
                        !move_uploaded_file($tmpName, $newName)){
        echo "<table><tr><td><strong>Failed to read file ".$_FILES['ufile']['name']."</strong></td></tr></table>";
   } else {
        echo "<br>";

        //coloca o conteudo do arquivo para a variavel $arquivo         
        $ponteiro = fopen ($_FILES['ufile']['name'],"r");
        $arquivo = '';
        while (!feof ($ponteiro)) {
         $arquivo = $arquivo.fgets($ponteiro,4096);

        }           
        fclose ($ponteiro);
        if (unlink($_FILES['ufile']['name']) != 1) echo "Erro ao deletar arquivo!";         

        $padrao = fnc_resgata_padrao($arquivo);

        if ($padrao == "COARRI"){
            $a = fnc_processa_coarri(trim($arquivo));

            prc_mostra_coarri($a);              
        }
        elseif ($padrao == "CODECO") {
            $a = fnc_processa_codeco(trim($arquivo));
            prc_mostra_codeco($a);              
        }
        else {
            echo "<table><tr><td><strong>Invalid file</strong></td></tr></table>";
        }           

   } 
} else {
     echo "You need to select a file.  Please try again.";
  }

The problem is, in this way only read the first line of the .EDI file and not all lines. I'm trying to understand that i must print an array but i don't know how to do it because my $a has the values i'm interested.

If the post is hard to understand, please let me know.

update 1

I just deleted some lines of the code, nothing important.