使用for / while循环获取数组中所有偶数的平均值？

I have a array and i need to get the average of all the EVEN numbers in the array i already have tried this but it still doesn't work.

$aReeks = array(23,245,1,2,12,-10,46,6,66,9999,-55,348,56,6,66,983); 
for ($q = 0; $q < count($aReeks); $q++)
      {
          { 
            if ($aReeks[$q] % 2 == 0)
            $totaaleven = array_sum($aReeks[$q]) / count($aReeks[$q]);
          }
      }
echo $totaaleven

I think this should work for you

$aReeks = array(23,245,1,2,12,-10,46,6,66,9999,-55,348,56,6,66,983); 

$evenSum = 0;
$evenCount = 0;

foreach($aReeks as $number) {
    if($number % 2 == 0) {
        $evenSum = $evenSum + $number;
        $evenCount++;
    }
}

$average = $evenSum / $evenCount;

You can filter your array using array_filter for even number, and simply divide sum with count, see below:

$aReeks = array(23,245,1,2,12,-10,46,6,66,9999,-55,348,56,6,66,983); 
$evenNos = array_filter($aReeks, function($value) {
    return !($value%2);
});
echo array_sum($evenNos)/count($evenNos);