PHP，使用fgets跳过文本文件的第一行和最后一行

I'm trying to figure out how to skip the first and last line of a text file when I'm reading it while using fgets(). The first line could be solved with an if(!$firstLine), but I'm not sure how to ignore the last line or if my solution for ignoring the first line is the best choice.

fgets($file); //Ignore the first line
$line = fgets($file);
$next = fgets($file); 
while ($next !== false) { //check the line after the one you will process next.  
                //This way, when $next is false, then you still have one line left you could process, the last line.
    //Do Stuff
    $line = $next;
    $next = fgets($file);
}

Unfortunately, file() will open file into "serial" stream (not sure if serial is right word), it means that you must read full file before detecting his end

$lines = file('http://www.example.com/');//or local file

unset($lines[0]);
unset($lines[count($lines)-1)]);
$new_file = implode('', $lines); //may want to use line break "
" for the join

try this

 $str= file_get_contents("file.txt");
 $arr = preg_split ("
",$str);
 $n = count($arr);

$n is a number of lines

$str="";
for($i=0;$i<$n;$i++){
   if($i>0 && $i<($n-1)){ $str.=$arr[$i]}
   }
    /**Str without line 1 and final line */

You might want to try exploding the file contents. It will help you alot! After that you will label it.