For my app I need to fetch the data from the database and mark fields accordingly. I am stuck with how to mark the radio button based on the value fetched. I am sharing the code I wrote to fetch the data and the radio button which I need to check.
$Medical_Record_Id=$_SESSION['Medical_Record_Id'];
$DOL=$_SESSION['DOL'];
$hour=$_SESSION['hour'];
$Question1="xxx";
$data1 = 'SELECT Option_Selected FROM Form1 WHERE Medical_Record = "'.$Medical_Record_Id.'" and DOL="'.$DOL.'" and hour="'.$hour.'" and Question="'.$Question1.'"' ;
$query = mysql_query($data1) or die("Couldn't execute query. ". mysql_error());
The html code which I have for the radio button is
<div>
<span>
<input type="radio" name="Gestational_age" class="field checkbox" value="<28" tabindex="7" />
<label class="choice" for="Gestational_age"><28</label>
</span>
<span>
<input type="radio" name="Gestational_age" class="field checkbox" value="28-31" tabindex="7" />
<label class="choice" for="Gestational_age">28-31</label>
</span>
<span>
<input type="radio" name="Gestational_age" class="field checkbox" value=">=32" tabindex="7" />
<label class="choice" for="Gestational_age">>=32</label>
</span>
</div>
Please guide me in how to check the radio button based on the value I am fetching in $query .
First of all, your HTML is really messed up. If you want to use symbols such as >, < in HTML attribute values or as text to display in the labels, you should convert them to the respective HTML entities, e.g., <, >.
After that, if you need to mark a value as selected, you should use the checked attribute on the specific <input> control:
<input type="radio" checked="checked" .... >
In order to show your input checked put some like below, see the second input
<form>
<input type="radio" name="Gestational_age" class="field checkbox" value="<28" tabindex="7">
<input type="radio" name="Gestational_age" class="field checkbox" value="28-31" tabindex="7" checked="checked">
<input type="radio" name="Gestational_age" class="field checkbox" value=">=32" tabindex="7">
</form>