从Mysql两个表中仅提取不包括时间的日期部分，并在php中进行比较

I have two tables in Database and both fields has the datetime columns I want to extract only the date part form the columns and compare it. MySql give the YYYY-MM-DD HH:MM:SS format and I can't compare because of the time difference even though the date is same.

SELECT * FROM  table1;
SELECT * FROM  table2;

table1.date == table2.date

How can I only compare date excluding time in PHP?

You can get date+time($table1_date) from Mysql and exclude time in PHP like this:

$full_date = strtotime($table1_date);
$date_only = date("d-m-Y", $full_date);

You can use MySQL's DATE_FORMAT() function to format the date, e.g.:

SELECT DATE_FORMAT(date,'%Y-%m-%d') FROM table;

Once you get the dates from both the tables, you can show/compare them in php.