我想在提交表单后创建一个带有三个按钮的弹出窗口。 我怎么做？

I have a form at addCharger.php, so when I click on the submit button, I want a popup window to come out, with three buttons likes:

  1. Ok
  2. Add Similar
  3. Add Different

So if I click on 'Add Similar' button on the popup window opens, it will direct me to addSimilarCharger.php and on that page I need the same values as the previous one in the form so I can add another charger.

If I click on 'Add Different' then it will direct me back to addCharger.php.If I click on 'Ok' then it will direct me to another page.

  1. Send data using ajax of form link
  2. on successful, pop up window using jquery dialog or any other moal dialog plugin link
  3. perform action based on your requirement

What Kasma is saying its true: but if you want to use jquery you have to download Jquery plugins on your pc and link to them or put this line in your head tags . but u need to be online always if u using that link . so start with small jquery fade in programs u will understand it and u will be able to do what you looking for