我怎么说“party1和party2有相同数量的选票”否则party1赢得了选举

EDIT

ok i have fixed any errors i have had now but the only thing im struggling to understand is why i dont get the name of the parties appearing on screen now!

<?php 
$id = $_GET['election'];

$result = mysql_query(
    sprintf("
        SELECT votes.party, COUNT(votes.vote_id)
        FROM votes
        WHERE election_id = %d
        GROUP BY election_id, votes.party
        ORDER BY COUNT(votes.vote_id) DESC",
        mysql_real_escape_string($id)
    )
);

// change is here

$votes = false;
$winners = array();

while ( ($row = mysql_fetch_row($result) ) && ( ($votes==false) || ($row['vote_count']===$votes) ) ) {
  $winners[] = $row['party'];
  $votes = $row['vote_count'];
}
echo '<hr><h3>'.'Results</h3><hr>'.'<h4>'.implode(' and ', $winners).' won with '.$votes.'</h4>';

?>

all i am getting on screen is 'and won with'. i am not getting the names of the parties to appear! anyone know?

They may be 2 winners but also 3, 4 ... who knows.

Here is the generic code that will display all the real winners:

// no change here

$id = $_GET['election'];

$result = mysql_query(
    sprintf("
        SELECT votes.party, COUNT(votes.vote_id) AS vote_count
        FROM votes
        WHERE election_id = %d
        GROUP BY election_id, votes.party
        ORDER BY COUNT(votes.vote_id) DESC",
        mysql_real_escape_string($id)
    )
);

// change is here

$votes = false;
$winners = array();
while ( ($row = mysql_fetch_assoc($result) ) && ( ($votes==false) || ($row['vote_count']===$votes) ) ) {
  $winners[] = $row['party'];// was missing the $ before row['party'];
  $votes = $row['vote_count'];
}

echo '<hr><h3>'.'Results</h3><hr>'.'<h4>'.implode(' and ', $winners).' won with '.$votes.'</h4>';