PHP - 按字母顺序排序数组值和echo输出字符串

Input Array

$userArr = array("0"=>"Veronica", "1"=>"Alex", "2"=>"Joe", "3"=>"Alex", "4"=>"Veronica");

Here, user Veronica and Alex are repeated twice. How do I sort above array reverse alphabetical way even if count of two users are same i.e. Veronica => 2, Alex => 2, only Veronica will be displayed as output string.

$userArr = array("0"=>"Veronica", "1"=>"Alex", "2"=>"Joe", "3"=>"Alex", "4"=>"Veronica");
$userCnt = array_count_values($userArr);
foreach ($userCnt as $key => $val) {
    echo "$key = $val
";
}

Output:

Veronica

Your Input Array:

$userArr = array("0"=>"Veronica", "1"=>"Alex", "2"=>"Joe", "3"=>"Alex", "4"=>"Veronica");

Count of an array:

echo count($userArr);

Reverse of an array:

arsort($userArr);
print_r($userArr);

Try this:

$userArr = array(
        "0"=>"Veronica", 
        "1"=>"Alex", 
        "2"=>"Joe", 
        "3"=>"Alex", 
        "4"=>"Veronica");

//below line will first create an associative array with 
//values as keys and their count as the value...
$arrayVals = array_count_values($userArr);

//next we sort this array in reverse alphabetically... 
krsort($arrayVals);

//finally, print it :)
print_r($arrayVals);

//will print...
Array
(
  [Veronica] => 2
  [Joe] => 1
  [Alex] => 2
)

UPDATE: Based on OP's explanation,I think he wants the value of the "last" alphabetical word in the array. If that is the case, the following code should do the trick:

$userArr = array("0"=>"Veronica", "1"=>"Alex", "2"=>"Joe", "3"=>"Alex", "4"=>"Veronica");
rsort($userArr);
echo current($userArr);

Using your approach, I'm assuming you want the one with the highest count that is also the last alphabetically:

$userArr = array("0"=>"Veronica", "1"=>"Alex", "2"=>"Joe", "3"=>"Alex", "4"=>"Veronica");
$userCnt = array_count_values($userArr);

ksort($userCnt);

$count = 0;
foreach ($userCnt as $key => $val) {
    if($val >= $count) {
        $result = $key;
        $count  = $val;
    }
}
echo "$result appeared $count times";

• Count the values
• Sort by key (names)
• Loop and check if the count ($val) is greater or equal to the last one

It seems to be even simpler with your new comments. Sort the original and grab either the first or last depending on sort order:

rsort($userArr);
echo current($userArr);
//or
sort($userArr);
echo end($userArr);

If you need the array_count_values() for whatever reason:

$userCnt = array_count_values($userArr);
krsort($userCnt);
echo key($userCnt);