Code example;
PHP Web Page: (index.php)
<html><head></head>
<body>
<?php
include("class_validation.php");
$val = new validation();
if(isset($_POST['action'])) doSomething();
function doSomething() {
$val->validate(); //I AM UNABLE TO DO THIS!
}
?>
</body>
</html>
PHP file: (class_validation.php)
<?php
class validation()
{
function validate(){
//some validation
}
}
?>
QUESTION: How can I call a function from the 'class_validation.php' file in a function I created in my PHP web page? I can correctly call the function doSomething() as well as call the function $val->validate(); when not located in another function. I there a way to do this?
$val is out of scope in that doSomething() function call. Pass it as a parameter to the function:
// Define the function to accept a parameter. Use a type hint to be sure it is
// a validation object
function doSomething(validation $val) {
$val->validate();
}
if(isset($_POST['action'])) doSomething($val);
(PHP documentation on type hinting)
Alternatively, and not recommended, you may use the global keyword inside the function to reference the global $val.
function doSomething() {
// Don't do it this way. The func parameter is preferred
global $val;
$val->validate();
}
You seems to be looking for closure support, which are only available for anonymous functions.
And according to your code sample, it doesn't seems to be a right use case. Maybe you should just pass this value as function parameter ?