如何使用PHP PDO从MYSQL查询中获取最后的结果？

I have a simple articles table with IDs. I want to get the highest and lowest ids from the latest 10 results. For example, if there are 11 ids, the result should be 2 and 11 and if there are 4 ids, should be 4 and 1 and so on. I use PHP PDO statements.

$aid = $DBH->prepare("SELECT id FROM articles ORDER BY id DESC LIMIT 10"); 
$aid->execute(); 
$row = $aid->fetch(PDO::FETCH_NUM, PDO::FETCH_ORI_LAST);
$lowest_article_id = $row[0];
$row = $aid->fetch(PDO::FETCH_NUM, PDO::FETCH_ORI_FIRST);
$highest_article_id = $row[0];

The above will always return 11 if there are 11 records and 10 if there are 10 records. So, the query ignores the PDO::FETCH_ORI_LAST part of the query.

Thanks

I did some checking and from the docs it sounds like this should work. You need to enable cursor scrolling when you prepare the sql.

$aid = $DBH->prepare("SELECT id FROM articles ORDER BY id DESC LIMIT 10", array(PDO::ATTR_CURSOR => PDO::CURSOR_SCROLL)); 
$aid->execute(); 
$row = $aid->fetch(PDO::FETCH_NUM, PDO::FETCH_ORI_LAST);
$lowest_article_id = $row[0];
$row = $aid->fetch(PDO::FETCH_NUM, PDO::FETCH_ORI_FIRST);
$highest_article_id = $row[0];

That being said it does not for me :/

I did more reading/testing and I found these two bug reports:
https://bugs.php.net/bug.php?id=34625 (this one is from 2005 though and I am almost positive there is cursor functionality in MySQL these days).
https://bugs.php.net/bug.php?id=57623

You can use the MIN and MAX functions in SQL to achieve this.

SELECT MIN(ID) min_ID, MAX(ID) max_ID
FROM
(
    SELECT id FROM articles ORDER BY id DESC LIMIT 10
)

Or use the union command in sql

SELECT min(id) id FROM articles UNION SELECT max(id) id FROM articles;

This statement returns the two ids you need.