JS二维对象数组中，如何求最大值的那一组name名称

dcc([
[{name:"A",value:33}, {name:"B",value:5}],
[{name:"C",value:24]}, {name:"D",value:10}],
[{name:"E",value:30}, {name:"F",value:9}],
[{name:"G",value:13}, {name:"H",value:25}]
])

我想求得二维数组dcc中的4个值，正确答案：ACEH

遍历列表，记录最大值及其所名称下标，遍历过程中，找到新的最大值，就修正。参考代码：

var lastNames = [];
var dcc = [
[{name:"A",value:33}, {name:"B",value:5}], 
[{name:"C",value:24}, {name:"D",value:10}],
[{name:"E",value:30}, {name:"F",value:9}],
[{name:"G",value:13}, {name:"H",value:25}]];

for(var i=0;i<dcc.length;i++){
  //内层遍历每个元素，元素的值还是一个数组
  var max = dcc[i][0].value;//默认最大值为第一个组
  var maxValueName = dcc[i][0].name ;
  for(var j=1;j<dcc[i].length;j++){
     if(max<dcc[i][j].value){
          //找到新最大值，修正
          max = dcc[i][j].value;
          maxValueName = dcc[i][j].name ;
        }
   }

   lastNames.push(maxValueName);
   console.log('maxValueName is '+maxValueName);
}

alert('last names are '+lastNames);

运行结果：

var dcc = [
        [{name:"A",value:33}, {name:"B",value:5}],
        [{name:"C",value:24}, {name:"D",value:10}],
        [{name:"E",value:30}, {name:"F",value:9}],
        [{name:"G",value:13}, {name:"H",value:25}]
    ]
    function find(name) {
        for (let i = 0; i < dcc.length; i++) {
            for (let j = 0; j < dcc[i].length; j++) {
                if (name == dcc[i][j].name) {
                    return dcc[i][j].value
                }
            }
        }
    }
    find('A') // 33