I have a server hosted on 1and1 and I am using Laravel. When I want to execute the Artisan command to schedule a tasks, I get this error:
$ php artisan schedule:run
Warning: Unexpected character in input: '\' (ASCII=92) state=1 in /htdocs/artisan on line 31
Parse error: syntax error, unexpected T_STRING in /htdocs/artisan on line 31
After a lot searches, nothing solved my issue (do an alias for PHP, call $ php5.5 instead $ php, etc.).
The main problem is that a call to php uses version 4.4.9 of PHP, instead 5.5 that Laravel needs.
$ php -v
PHP 4.4.9 (cgi-fcgi) (built: Mar 31 2016 16:41:29)
Copyright (c) 1997-2008 The PHP Group
Zend Engine v1.3.0, Copyright (c) 1998-2004 Zend Technologies
$ php5.5 -v
PHP 5.5.35 (cgi-fcgi) (built: May 3 2016 07:09:03)
Copyright (c) 1997-2015 The PHP Group
Zend Engine v2.5.0, Copyright (c) 1998-2015 Zend Technologies
I changed the call to php5.5 and altered the Artisan file, calling this on the first line:
#!/usr/local/bin/php5.5
<?php
But at the end I always get this from artisan module calls:
Running scheduled command: '/usr/local/bin/php' 'artisan' moneySaved:send >> './logs/log.log' 2>&1 &
So the problem must come from who generates those "Running scheduled command" lines.
After a research, the problem was in the way that Symfony internal scripts "locate" the php path to call it. Specifically those:
epoc/vendor/symfony/process/PhpExecutableFinder.php epoc/vendor/laravel/framework/src/Illuminate/Console/Scheduling/Schedule.php
The binary var holds the path to call PHP. In my case I forced it to use the 1and1 path for php5.5, and that's all.
public function command($command, array $parameters = []) {
//$binary = ProcessUtils::escapeArgument((new PhpExecutableFinder)->find(false));
$binary = "/usr/local/bin/php5.5";
if (defined('HHVM_VERSION')) {
$binary .= ' --php';
}
if (defined('ARTISAN_BINARY')) {
$artisan = ProcessUtils::escapeArgument(ARTISAN_BINARY);
} else {
$artisan = 'artisan';
}
return $this->exec("{$binary} {$artisan} {$command}", $parameters);
}
Now it works!