使用参数中的数组进行ajax查询

I'm trying to make an Ajax query with an array in the parameters. Here's an example :

var info = [ter,ter,ter];

$('body').on('click','#upload', function(){
    $.ajax({
        url:'/app_dev.php/uploader_photos',
        data:{
            links : info,
        },
        dataType : 'json',
        beforeSend : function(){
            $('#upload_photo').empty();
            $('#upload_photo').append('<i class="fa fa-refresh fa-spin"></i> Loading');
        },
        success : function(data){
            $('#upload_photo').empty();
            $('#upload_photo').append('<i class="fa fa-thumbs-o-up"></i> OK');
        }
    });
});

The issue is my url is encoded this way :

/upload?links%5B%5D=ter&lioks%5B%5D=ter&lioks%5B%5D=ter

What i need to know how to encode it this way :

/upload?links=[ter,ter,ter]

Thanks for the help !

That shouldn't be a problem actually. As you have not set the Content-Type so by default jQuery uses formurlencoded query string so it encodes the values that way and it sends it as a form data instead of Request Payload.

You can get it like:

if(isset($_GET['links'])){
  echo $_GET['links'];
}

From the docs:

contentType (default: 'application/x-www-form-urlencoded; charset=UTF-8') Type: Boolean or String
When sending data to the server, use this content type. Default is "application/x-www-form-urlencoded; charset=UTF-8", which is fine for most cases. If you explicitly pass in a content-type to $.ajax(), then it is always sent to the server (even if no data is sent). As of jQuery 1.6 you can pass false to tell jQuery to not set any content type header. Note: The W3C XMLHttpRequest specification dictates that the charset is always UTF-8; specifying another charset will not force the browser to change the encoding. Note: For cross-domain requests, setting the content type to anything other than application/x-www-form-urlencoded, multipart/form-data, or text/plain will trigger the browser to send a preflight OPTIONS request to the server.

This will convert a native JavaScript object to a JSON string:

JSON.stringify(yourString);

so, in your code:

links : JSON.stringify(info),

Stringify your array to json:

info = JSON.stringify(info);

in your php:

$info = json_decode($_POST['links']);