MySQLi!=没有处理多个AND / OR子句

So I have two rows in my Database - user_one and user_two, these rows are occupied by User ID's as numbers for a messaging system, I have also included a support ticket system within the same message feature but am having a few issues with this code snippet...

$sqlc="SELECT * FROM ap_conversations WHERE user_one = '$user_id' AND user_two != '999' OR user_two = '$user_id' AND user_one != '999' OR user_one = '$user_id' AND user_two != '999d' OR user_two = '$user_id' AND user_one != '999d'";

As you'll notice, the support tickets ID is 999, and when it was kept to just checking that neither ID's were 999 this code worked perfectly. Although I also need it to check that neither user_one or user_two has ID's of 999 or 999d. This current code returns 1, when I know for a fact it should return 0 so I know something is defiantly going wrong and I think I may have it set up incorrectly. I have attempted to set it up like this in many different formats:

$sqlc="SELECT * FROM ap_conversations WHERE user_one = '$user_id' AND (user_two != '999' OR user_two != '999d') OR user_two = '$user_id' AND (user_one != '999' OR user_one != '999d')";

But still get the same results? Can anybody tell me what I am doing wrong here or how I can make this code perform better?

   (user_one = '$user_id' AND user_two != '999')
OR (user_one = '$user_id' AND user_two != '999d') 

...is a problem, it simplifies to user_one = '$user_id', the AND conditions become irrelevant.

If you don't believe me, try a row where user_one = user_id and user_two = '999'.. It fails the first bracketed condition, but passes the second and is returned.

I assume you want:

SELECT * FROM ap_conversations 
 WHERE (user_one = :user_id AND user_two NOT IN ('999','999d')) 
    OR (user_two = :user_id AND user_one NOT IN ('999','999d'));

N.B. Passing in '999' or '999d' as the $user_id will still return the support tickets. I quite like this functionality but if this is not desired you could use:

SELECT * FROM ap_conversations 
 WHERE (user_one = :user_id OR user_two = :user_id) 
   AND user_one NOT IN ('999','999d')
   AND user_two NOT IN ('999','999d');

You need to use parenthesis to establish operator precedence:

$sqlc="SELECT * FROM ap_conversations 
WHERE (user_one = '$user_id' AND user_two != '999') 
OR (user_two = '$user_id' AND user_one != '999') 
OR (user_one = '$user_id' AND user_two != '999d') 
OR (user_two = '$user_id' AND user_one != '999d')";

Try to add brackets in your query as below :

$sqlc="SELECT * FROM ap_conversations WHERE (user_one = '$user_id' AND user_two != '999') OR (user_two = '$user_id' AND user_one != '999') OR (user_one = '$user_id' AND user_two != '999d') OR (user_two = '$user_id' AND user_one != '999d')";