i have a carousel on my website and wish to load images from database, although the carousel is working fine, but the images are not loading
Database View
id image1 image2 image3
1 carouselimage/image1 carouselimage/image1 carouselimage/image1
there wouldbe only one row in this table
code for carousel
<?php
require 'connection.php';
echo "<header id='myCarousel' class='carousel slide'>";
echo "<ol class='carousel-indicators'>";
echo "<li data-target='#myCarousel' data-slide-to='0' class='active'></li>";
echo "<li data-target='#myCarousel' data-slide-to='1'></li>";
echo "<li data-target='#myCarousel' data-slide-to='2'></li>";
echo "</ol>";
echo "<div class='carousel-inner'>";
$sql = "SELECT * FROM carousel_image ";
$result = mysqli_query($con, $sql);
if (mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_array($result))
{
$image1=$row['image1'];
$image2=$row['image2'];
$image3=$row['image3'];
echo "<div class='item active'>";
echo "<div class='fill' style='background-image:url('http://example.com/carouselimage/" .$image1."\' height=\'500\' width=\'2000\'/);></div>";
echo "</div>";
echo "<div class='item'>";
echo "<div class='fill' style='background-image:url('http://example.com/carouselimage/" .$image2."\' height=\'500\' width=\'2000\'/);></div>";
echo "</div>";
echo "<div class='item'>";
echo "<div class='fill' style='background-image:url('http://example.com/carouselimage/" .$image3."\' height=\'500\' width=\'2000\'/);></div>";
echo "</div>";
}
}
echo "</div>";
echo "<a class='left carousel-control' href='#myCarousel' data-slide='prev'>";
echo "<span class='icon-prev'></span>";
echo "</a>";
echo "<a class='right carousel-control' href='#myCarousel' data-slide='next'>";
echo "<span class='icon-next'></span>";
echo "</a>";
echo "</header>";
mysqli_close($con);
?>
would appreciate if someone could help me with the code
Your problem is probably not the SQL, but this line of PHP/HTML and CSS:
echo "<div class='fill' style='background-image:url('http://example.com/carouselimage/" .$image1."\' height=\'500\' width=\'2000\'/);></div>";
^ a ' opens style and ^ this ' closes style again
So you gotta fix your quotes, and as well:
echo "<div style='[..]height=\'500\' width=\'2000\'/);></div>";
^^^^^^^^^^^^^^^^^ height/width within style="" shouldn't have = or a quote
Honestly this is basic HTML/CSS, so I would advise you to look at w3schools to learn how to prevent these mistakes. It should be something like this:
echo '<div class="fill" style="background-image:url(http://example.com/carouselimage/' . $image1 . ');height:500px;width:2000px;"></div>';