php中的数据库连接问题

I have been creating registration form using php.

And my database and table look like this:

http://imgur.com/b6JhFcd

This is the database connection query:

<?PHP
require_once("./include/fg_membersite.php");

$fgmembersite = new FGMembersite();

//Provide your site name here

//Provide the email address where you want to get notifications
$fgmembersite->SetAdminEmail('rajaselva.csc@gmail.com');

//Provide your database login details here:
//hostname, user name, password, database name and table name
//note that the script will create the table (for example, fgusers in this case)
//by itself on submitting register.php for the first time
$fgmembersite->InitDB(/*hostname*/'localhost',
                      /*username*/'root',
                      /*password*/'',
                      /*database name*/'employee',
                      /*table name*/'employee-reg');

//For better security. Get a random string from this link: http://tinyurl.com/randstr
// and put it here
$fgmembersite->SetRandomKey('qSRcVS6DrTzrPvr');

?>

After entering the input details, it shows like this,

http://imgur.com/8RETiOp

May I know, what is my mistake, how can I fix this.

Can anybody help me? thanks in advance.

Add back tick (``) on the employee-reg table name. Hope that will work

$fgmembersite->InitDB(/*hostname*/'localhost',
                      /*username*/'root',
                      /*password*/'',
                      /*database name*/'employee',
                      /*table name*/'`employee-reg`');

Problem is with your table name you should not user minus(-) sign in your table name. If you really need to use it then enclose it with back-ticks (`). See the Example Below:

CREATE TABLE `employee-reg` (id int, name varchar( 255 )); //Works Well

CREATE TABLE employee-reg (id int, name varchar( 255 )); //Will Not Work and gives error

Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '-reg (id int, name varchar( 255 ))' at line 1

Quite Similar to your error. So either remove minus(-) sign or use back-ticks(`).