退出并在PHP / HTML中显示错误消息

I am checking if a particular value is set using isset. I want to quit the HTML with displaying error message like "name not found , Enter a valid name". Currently I am checking like

if ((! isset($_GET["name"])) or (! is_dir($_GET["name"])) or (empty($_GET["name"]))) {

    Print "Name not found, Enter a valid name"
}

After the print, I want to exit without further execution of HTML code. how can I exit with the my error message and no default error message from PHP

Thanks

Die or exit: see the php documentation

http://php.net/die

http://php.net/exit

die ("I'm dyin over here");

 die("Name not found, Enter a valid name");

That should help!

Regards, Felix

You would use the die or exit methods. This will halt all PHP and HTML from being displayed or executed.

Example:

if ((! isset($_GET["name"])) or (! is_dir($_GET["name"])) or (empty($_GET["name"]))) {

    die("Name not found, Enter a valid name");
}