自己实现的array_unique（）[重复]

I have this array:

$number = array("a", "b", "b", "c", "a", "b", "c", "b", "c");

Now I want to get all unique values. Means the result should be:

$result = array("a", "b", "c");

Now I know that this can easily be solved with array_unique(). But I want to write my own little implementation of array_unique() just using a for loop, unset() and array_values().

</div>

use array_unique()

<?php
    $number=array("a","b","b","c","a","b","c","b","c");
    $unique_array=array_unique($number);
    print_r($unique_array);
?>

//second posibility

<?php
    $number=array("a","b","b","c","a","b","c","b","c");
    $unique_array=[];
    foreach($number as $val)
    {
        $unique_array[$val]=$val;
    }
    print_r(array_values($unique_array));
?>

//Third posibility with for,unset,array_value

<?php
$number=array("a","b","b","c","a","b","c","b","c");
$count=count($number);
for($i=0;$i<$count;$i++)
{
    if($i<count($number))
    {
        for($j=$i+1;$j<$count;$j++)
        {
            if($number[$i]==$number[$j])
            {
                unset($number[$j]);
             }
        }

    }
}
$number=array_values($number);
print_r($number);

?>

expected result is

Array ( [0] => a [1] => b [2] => c ) 

Something like this maybe? Here we are looping through and array starting in one for from the position 0 and in the other from 1. We compare the $i position with all the others in array and if it finds two same it removes the second one.

<?php
    $number = array("a", "b", "b", "c", "a", "b", "c", "b", "c");
    $count = count($number);

    for($i = 0; $i < $count; $i++) {
        for($j = $i+1; $j < $count; $j++) {
            if(isset($number[$j]) && isset($number[$i]) && $number[$i] == $number[$j]) {
                unset($number[$j]);
            }
        }
    }

    print_r($number);