The Code is like this:
$url = array("http://www.samples.com/rss"
" ............ "
" ............ " );
for($j=0;$j<count($url);++$j){
$num = $j + 1;
$xmlDoc = new DOMDocument();
$xmlDoc->load($url[$j]);
//get elements from "<channel>"
$channel=$xmlDoc->getElementsByTagName('channel')->item(0);
$channel_title = $channel->getElementsByTagName('title')->item(0)->childNodes->item(0)->nodeValue;
$channel_link = $channel->getElementsByTagName('link')->item(0)->childNodes->item(0)->nodeValue;
$channel_desc = $channel->getElementsByTagName('description')->item(0)->childNodes->item(0)->nodeValue;
$x=$xmlDoc->getElementsByTagName('item');
for ( $i = 0 ; $i < $x->length ; ++$i ){
1) for Title $item_title=$x->item($i)->getElementsByTagName('title')->item(0)->childNodes->item(0)->nodeValue;
2) for link $item_link=$x->item($i)->getElementsByTagName('link')->item(0)->childNodes->item(0)->nodeValue;
3) for description $item_desc=$x->item($i)->getElementsByTagName('description')->item(0)->childNodes->item(0)->nodeValue;
$query[$j]['title'] = $item_title;
$query[$j]['field'] = "xml";
$query[$j]['id'] = $item_link;
$query[$j]['description'] = $item_desc;
}
}
I want to get first img at 3) for descriptoin. Maybe there are many img in desription. But I want first img. How can I pick up img or src?
The description of an RSS document is not specified. In the most cases it will contain an XML fragment (an xml without a root element). It is try and error. Try adding an xml element around and parse the description value as an separate document. This is your best chance.