如何跳过PHP的致命错误

This is a demo code in the line 6 there is a function find() actually this function doesn't exist and when i run this file I got error
Fatal error: Call to undefined function find() in C:\xampp18\htdocs\demo\exp.php on line 6
my question is that is this possible in PHP to handle this type error i.e. want to print Line 2: 5 which is after the first if block. thanks in advance.

<?php 
$a=10;
if(true)
{
    echo "Line 1: ".$a/find();
}

if (true)
{
    $b=2;
    echo "<br>Line 2: ".$a/$b;
}
?> 

that's not good idea. what about check whether find() is exist or not using function_exists. example:

<?php 
$a=10;
if(true) {
    echo "Line 1: " . (function_exists('find') ? $a/find() : $a);
}

if (true) {
    $b=2;
    echo "<br>Line 2: ".$a/$b;
}
?>