将curl命令转换为PHP

I have this command

curl -k '"url."' -d 'APACScommand=NewRequest' -d 'data="XML"

I want to use the curl library of PHP.

I guess for -k flag I just call

curl_init($url)

I know that -d stands for data. Should I use something like this?

curl_setopt($handle, CURLOPT_POSTFIELDS, $data);

I see there are two data flag, isn't the second one going to override the first?

Edit

I've seen that -k flag may be replaced by

curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);

is it correct?Or it isn't even necessary to add it?

Can you try this, use http_build_query

 $data = array('APACScommand'=>'NewPayment',
          'data'=>$command
          );

$ch=curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_ANY);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, false);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($data));
$reply=curl_exec($ch);
curl_close($ch);

Ref: http://php.net/manual/en/function.curl-setopt.php

Just build the data as an array:

$data = array('APACScommand' => 'NewRequest', 
              'data' => 'XML');

And then simply pass this:

curl_setopt($handle, CURLOPT_POSTFIELDS, $data);