I have a problem, how to display the image and the url stored in the destination database.
This my format code :
<a href="<?php echo get_settings('home'); ?>" style="border:0;">
<img src="<?php echo get_settings('home');?>/banner/728x90.JPG" width="728" height="90"/>
</a>
This code is stored in the database
<a href=\"<?php echo get_settings(\'home\'); ?>\"
style=\"border:0;\">
<img src=\"<?php echo get_bloginfo(\'template_directory\');?>/banner/728x90.JPG\"
width=\"728\" height=\"90\"/>
</a>
I called using:
stripslashes(get_option("bh"));
the results
<a href="<?php echo get_settings('home'); ?>" style="border:0;">
<img src="<?php echo get_bloginfo('template_directory');?>/banner/728x90.JPG" width="728" height="90"/>
</a>
$bh = html_entity_decode(get_option("bh"));
the results
\" style=\"border:0;\"> /banner/728x90.JPG\" width=\"728\"
height=\"90\"/>
of all that I do still could not bring the image together with the url.