如何按出生日期获得年龄[关闭]

I want get the exact age of the following date in var $birth_date by php, How is it?

$birth_date = 2011/12/16;

$birth_date => For example, this is my birth date.

For example output from my birth date is: 0 Year, 0 Month, 1 Day

Using unix timestamps to handle birthdates is a bad idea, as their range is only very limited (1970-2038). Use php's builtin DateTime class instead:

$then = DateTime::createFromFormat("Y/m/d", "2011/12/16");
$diff = $then->diff(new DateTime());
echo $diff->format("%y year %m month %d day
");

<?php

  //calculate years of age (input string: YYYY-MM-DD)
  function birthday ($birthday, $separator){
    list($year,$month,$day) = explode($separator, $birthday);
    $year_diff  = date("Y") - $year;
    $month_diff = date("m") - $month;
    $day_diff   = date("d") - $day;
    if ($day_diff < 0 || $month_diff < 0)
      $year_diff--;
    return $year_diff;
  }
  echo getAge('2010/12/16', '/');
?>

Reformatted from http://snippets.dzone.com/posts/show/1310

I also recommend the Tizag PHP tutorial.