如何选择等于值的名称数量并保存找到的变量中的搜索次数[关闭]

I'm trying to select the number of names in the database equal to "dog", and save the number of searches found into a variable php? e.g number of dogs found = 4;. Where I can store this as a variable.

So far I got this:

SELECT id, COUNT(id) FROM `profiledb` GROUP BY id

Use it like this, assuming your name field

SELECT name, COUNT(id) as number_of_searches FROM profiledb WHERE name = 'dog'