在php中发送复选框值

Does anyone knows how to code in php for every time i tick the check-box in my form? And when i tick the check-box,the value is suppose to actually inserted into an id column in my database and it will auto increase every time i tick and submit the form.

You need to use ajax. Following is the code snippet.

$('input:radio[name="tickExam"]').click(function() {
if(this.checked){
        $.ajax({
            type: "POST",
            url: 'increase.php',
            data: {id:$(this).val()},
            success: function(data) {
                alert('Increased.....');
            },
             error: function() {
                alert('Sorry! there was an issue');
            }
        });

        }
  });

in increase.php write your code to increase value in table.

Ok, so you have this :

<form ...>
    <table>
        <tr>
            <td>
            </td>
            //...
            <td>
                <input type='checkbox' value='YOUR_ID' name='checkboxarray[]'/>
            </td>
        </tr>
    </table>
    <input name='submit' type='submit' ...>
</form>

You want that on submit, the corresponding ID database record "counter field" to be increased by 1 'IF THE BOX IS CHECKED'

then, do that :

//if you posted : 
if(isset($_POST['submit'])){
    //here you have to handle your data
    //your checkbox array is not empty IF there is something checked, so : 
    if(is_array($_POST['checkboxarray'])){
        foreach($_POST['checkboxarray'] as $value){
            //HERE YOUR $VALUE IS THE ID OF THE DB RECORD (if you dit id the way I explain it over), so do your database stuff here, just increase your field WHERE id = $value !
        }
    }else{
        //no checkboxes checked
    }
}else{
    //nothing posted, just display your form
}

Is that what you need?

Does anyone knows how to code in php for every time i tick the check-box in my form? And when i tick the check-box,the value is suppose to actually inserted into an id column in my database and it will auto increase every time i tick and submit the form.

considering your post when you say "every time i tick AND SUBMIT THE FORM", then there is no need to use javascript or ajax in your case