I have a string like so {!Hello} there, {!World}. I need to match {!Hello} and {!World} and I have my regex like so
$text = '{!Hello} there, {!World}';
preg_match_all("/\{\!.+\}/",$text,$var);
The problem is it matches the whole thing from beginning to end. That obviously means it's not stopping at the first occurrence of } but rather the last one. How can I match those?
EDIT: Forgot to mention I can't use \w+ because the word in between the brackets may contain special characters. IT may be something like {!Email__email@some.domain__IsInvalid}. I need to match this whole thing
You basically need to match ungreedy:/\{\!.+?\}/
$text = '{!Hello} there, {!World} foo {!Email__someemail@some.domain__IsInvalid}';
preg_match_all("/\{\!.+?\}/",$text,$var);
print_r($var);
You could also add the U modifier (note it's uppercase):/\{\!.+\}/U
$text = '{!Hello} there, {!World} foo {!Email__someemail@some.domain__IsInvalid}';
preg_match_all("/\{\!.+\}/U",$text,$var);
print_r($var);
http://phpfiddle.org/lite/code/31z-rtu
preg_match_all("/\{\!.+?}/",$text,$var);
I misplaced the ? operator first. PHP understands the ? operator, it does exactly what you ask for, it limits the matches to the first occurence.
Hih.
What you need is: /\{\![^\}]*\}/
It looks for characteres that are not a }, between {! and }
Try this regex:
`\{(\![^\{]+)\}`
In your pattern .+ is a greedy and it will match as much as possible. For example:
In examples:
{!Hello} there, {!World}}
{!Hello} there, {!World}} dsad
bold part are the matches found by your regex.
In my pattern:
[^\{] this part is also present with + which means greedy but it i have restricted it match till the { due to ^ sign in character class.
Hope it will help you!