解析错误：语法错误，php图像路径上出现意外[关闭]

I am trying to display all images on a page using this query.. however it is giving me syntax problem.. Parse error: syntax error, unexpected '>'

<?php               
    $result = mysql_query("SELECT * FROM my_image, $connection);
    while($row = mysql_fetch_array($result))
    {
        echo "<div><img src=\"uploadedimages/".$row['name']."\" /></div>"
    }       
?> 

anyone knows whats wrong?

You're missing a closing double quote:

mysql_query("SELECT * FROM my_image", $connection);
                                   ^

You're missing a terminating semi-colon:

echo "<div><img src=\"uploadedimages/".$row['name']."\" /></div>";
                                                                 ^

May I recommend:

echo '<div><img src="uploadedimages"' . $row['name'] . '" /></div>';

Also, stop using mysql_ functions. They are no longer maintained and are officially deprecated. See the red box? Learn about prepared statements instead, and use PDO or MySQLi - this article will help you decide which. If you choose PDO, here is a good tutorial.